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IP Address

 

A. Awadhi


  1. You have class B Address with 100 Subnets & 500  usable hosts. What is the subnet mask?

 

Answer:

 

Class B is   N.N.H.H

100 Subnets means 2^7=128, then we need 7 bits for network

255.255.1111111

0.00000000

 

Which is  255.255.254.0

2.   Given 213.105.72.0/28

      What is usable subnet & host addresses the above 
       address can provide?

 

Answer:

 

/28 means the number of 1's in the subnet mask, which is 255.255.255.240 in binary will be

255.255.255.

11110000

 

Host: 2^4-2=14 usable address

Network: 2^4-2=14 usable address


 

      3.  Given 210.106.14.0/24

     What is usable subnet & host addresses the above  
     address can provide?

 

Answer:

 

/24 means the number of 1's in the subnet mask, which is 255.255.255.0. There are 2^8=256 hosts address (254 usable addresses) & 2^0=1 Network address.

4.   Given subnet mask 255.255.255.224

      What is the valid IP Address from the below?

 

      (a) 92.11.178.93 

      (b) 134.178.18.56

      (c) 192.168.18.63

      (d) 192.168.16.87 

      (e) 134.178.19.192

 

Answer:

 

The only way to solve this question is to check each choice.

 

First find out the number of host digits form the subnet mask by writing the last digit in binary as below and then compared to each of the given choices.

 

 

255.255.255.111

00000

 

(a)

92.11.178.   010 

11101

 

(b)

134.178.18.  001

10111

 

(c)

192.168.18.  001

11111

This is a Broadcast address and therefore not a valid address

(d)

192.168.16.  010

10111

 

(e)

134.178.19.  110

00000

This is a Network address and therefore not a valid address

 


 
 

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